Sir recurent

Moderators: Bogdan Posa, Laurian Filip

Post Reply
alex2008
Leibniz
Posts: 464
Joined: Sun Oct 19, 2008 3:23 pm
Location: Tulcea

Sir recurent

Post by alex2008 »

Stiind ca \( 6a_1=12a_2=20a_3= ... =(n+1)(n+2)a_n \), \( a_1+a_2+a_3+...+a_n=5760 \) si \( a_{n-1}-a_n=40 \), sa se afle \( n \) si termenii \( a_1 \) si \( a_8 \).
Top
User avatar
Andi Brojbeanu
Bernoulli
Posts: 294
Joined: Sun Mar 22, 2009 6:31 pm
Location: Targoviste (Dambovita)

Post by Andi Brojbeanu »

Esti sigur ca enuntul e corect?
Top
Post Reply

Return to “Clasa a VII-a”