O inegalitate cu numere care au suma cuburilor nula

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Marius Dragoi
Thales
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O inegalitate cu numere care au suma cuburilor nula

Post by Marius Dragoi »

Fie \( x_1,x_2,....,x_n \geq -1 \) si \( \sum_{i=1}^{n} {x_i^3} =0 \).

Sa se arate ca: \( \sum_{i=1}^{n} {x_i} \leq 1 \) , unde \( n \in N* \).
Politehnica University of Bucharest
The Faculty of Automatic Control and Computers
Marius Mainea
Gauss
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Joined: Mon May 26, 2008 2:12 pm
Location: Gaesti (Dambovita)

Post by Marius Mainea »

\( \sum_{i=1}^{n}{(x_i+1)(x_i^2-x_i+\frac{1}
{2})}\ge 0 \)
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