Ecuatie exponentiala

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Razvan Balan
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Ecuatie exponentiala

Post by Razvan Balan »

\( $9^x-5^x-4^x=2 \sqrt{2^x}$ \)
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turcas
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Post by turcas »

nu e cumva acolo \( 2 \sqrt{20}^x \) ? .

Daca da , atunci ecuatia este echivalenta cu :

\( 9^x = ( \sqrt{5}^x + \sqrt{4}^x)^2 \) adica :

ajungem la o ecuatie cu solutia unica \( x = 2 \) .
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