Multimi

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Marcelina Popa
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Multimi

Post by Marcelina Popa »

Sa se determine multimea:
\(
A=\{x\in [-1,1]/\frac{2x-1}{3}\in \mathbb{Z}\} \)
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mihai++
Bernoulli
Posts: 206
Joined: Wed Nov 28, 2007 8:08 pm
Location: Focsani

Post by mihai++ »

\( -1\leq x\leq1\Rightarrow -3\leq2x-1\leq1\Rightarrow -1\leq\frac{2x-1}{3}\leq\frac{1}{3}\Rightarrow 2x-1\in\{0,-3\}\Rightarrow A=\{\frac{1}{2},-1} \)
n-ar fi rau sa fie bine :)
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