Ecuatie in numere reale

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alex2008
Leibniz
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Ecuatie in numere reale

Post by alex2008 »

Sa se rezolve ecuatia:

\( 3^{x+1}=(x-1)(x-3) \)
. A snake that slithers on the ground can only dream of flying through the air.
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Marius Mainea
Gauss
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Location: Gaesti (Dambovita)

Post by Marius Mainea »

1) Daca \( x\in (-\infty,1) \), \( x=0 \) solutie unica.

2) Daca \( x\in(3,+\infty) \) nu avem solutii, deoarece daca \( x\in[n,n+1),n\ge 3 \), atunci \( 3^{x+1}\ge3^{n+1}>n(n-2)>(x-1)(x-3) \).
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