Trapez si unghiuri congruente

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Filip Chindea
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Joined: Thu Sep 27, 2007 9:01 pm
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Trapez si unghiuri congruente

Post by Filip Chindea »

Diagonalele unui trapez \( ABCD \) se taie in \( P \). Punctul \( Q \) se afla intre dreptele paralele \( BC \) si \( AD \) astfel incat \( \angle AQD = \angle CQB \), iar \( CD \) separa \( P, Q \). Sa se arate ca \( \angle BQP = \angle DAQ \).

[ IMO Shortlist 2007, G3 ]
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