Multimea divizorilor

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Filip Chindea
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Joined: Thu Sep 27, 2007 9:01 pm
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Multimea divizorilor

Post by Filip Chindea »

Fie \( a > 1 \) cu multimea primelor care divid cel putin unul din numerele \( \left\{ \lfloor a^k \rfloor \ : \ k \in \mathbb{N}^{\ast} \right\} \) finita. Aratati ca \( a \in \mathbb{Z} \).
Life is complex: it has real and imaginary components.
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