Shortlist 9
Posted: Sun Mar 28, 2010 7:52 pm
Fie a,b,c numere strict pozitive, subunitare cu suma 1. Demonstrati ca:
\( \sum\frac{log^2_{ab}c}{a+b}\ge\frac{9}{8} \).
Tudorel Lupu, Constanta, Shortlist 2003
\( \sum\frac{log^2_{ab}c}{a+b}\ge\frac{9}{8} \).
Tudorel Lupu, Constanta, Shortlist 2003