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Inegalitate simpluta, 1

Posted: Thu Feb 04, 2010 6:41 pm
by Claudiu Mindrila
Fie \( x, \ y, \ z>0 \). Sa se arate ca: \( \frac{x\left(y+z\right)}{z+yz}+\frac{y\left(z+x\right)}{y+zx}+\frac{z\left(x+y\right)}{z+xy}\le2\left(\frac{x^{2}}{x+yz}+\frac{y^{2}}{y+zx}+\frac{z^{2}}{z+xy}\right) \)

Stefan Gavril

Posted: Fri Feb 05, 2010 1:44 pm
by Marius Mainea
\( \sum\(\frac{xy}{x+yz}+\frac{yx}{y+zx}\)\le\sum\(\frac{x^2}{x+yz}+\frac{y^2}{y+zx}\) \)