Asemanatoare cu o problema din longlist Canberra
Posted: Mon Dec 15, 2008 10:22 am
Impartiti multimea \( A=\{1,2,3,\dots,1000\} \) in 2 submultimi \( A_1 \) si \( A_2 \) cu urmatoarele proprietati:
\( (i)A_1\cup A_2=A \);
\( (ii)A_1\cap A_2=\phi \);
\( (iii)\sum_{x\in A_1} x^2=\sum_{x\in A_2} x^2 \).
\( (i)A_1\cup A_2=A \);
\( (ii)A_1\cap A_2=\phi \);
\( (iii)\sum_{x\in A_1} x^2=\sum_{x\in A_2} x^2 \).