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Concursul "Nicolae Paun", 2008, problema 3
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Concursul "Nicolae Paun", 2008, problema 3
Posted:
Sat Dec 13, 2008 8:08 pm
by
Claudiu Mindrila
Sa se arate ca ecuatia
\( a^2+b^2-8c=6 \)
nu are solutii in multimea numerelor intregi.
Posted:
Sat Dec 13, 2008 11:28 pm
by
Marius Mainea
Se foloseste faptul ca
\( a^2\equiv 0 , 1 , 4 (mod8) \)