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M.A. A,B,C,D= 5
B,C = 5
A, ,D= 5

Stiind ca cele 4 numere < 10... aflati variantele

Draguta problema , Amaranth !

\( \frac {a+b+c+d}{4}=5 \) => a+b+c+d = 20
\( \frac {b+c}{2}=5 \) => b+c = 10
\( \frac{a+d}{2}=5 \) => a+d = 10

1. a = 1 => d = 9
b = 2 => c = 8

2. a = 1 => d = 9
b = 8 => c = 2

3. a = 2 => d = 8
b= 3 => c = 7

4 . a = 2 => d = 8
b = 7 => c = 3

5. a = 3 => d = 7
b = 4 => c= 6

6. a = 3 => d = 7
b = 6 => c = 4

7. a = 7 => d = 3
b= 6 => c = 4

8. a=7 => d = 3
b= 4 => c = 6

9. a = 8 => d = 2
b = 7 => c = 3

10. a = 8 => d = 2
b = 3 => c = 7


11. a = 9 => d = 1
b = 8 => c= 2

12. a= 9 => d = 1
b =2 => c = 8

Dap... erau cifre cu suma 10...