Inegalitate by Vasc
Posted: Mon Oct 13, 2008 9:30 am
Demonstrati ca pentru orice \( a,b,c\in (0, \infty) \), cu \( abc=1 \) are loc inegalitatea: \( \frac{a}{b}+\frac{b}{c}+\frac{1}{a}\geq \sqrt{3(a^2+b^2+1)} \).
Vasile Cirtoaje, Revista Minus 2/2008
Vasile Cirtoaje, Revista Minus 2/2008