a^2+b^2+c^2=3...
Posted: Tue Jun 24, 2008 2:03 pm
Fie a, b, c, x, y,z numere reale pozitive astfel incat \( a^2+b^2+c^2=3. \) Atunci:
\( \frac{x}{a}+\frac{y}{b}+\frac{z}{c}\geq sqrt {xy}+sqrt {yz}+\sqrt {zx} \)
Marius Damian SHL 2006
\( \frac{x}{a}+\frac{y}{b}+\frac{z}{c}\geq sqrt {xy}+sqrt {yz}+\sqrt {zx} \)
Marius Damian SHL 2006