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alex2008
Leibniz
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Sir

Post by alex2008 »

Se considera sirul \( (x_n)_{n\ge 1} \) definit prin \( x_1=x_2=1 \) si \( x_{n+1}=\sqrt{nx_n+x_{n-1}}\ ,\ (\forall)n\ge 2 \) . Determinati \( [x_n] \) , pentru \( n\ge 3 \) .


Constantin Caragea
. A snake that slithers on the ground can only dream of flying through the air.
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baleanuAR
Euclid
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Location: Motru, Gorj

Post by baleanuAR »

Se arata inductiv ca \( n-2\leq x_n<n-1 \) pentru \( n\geq3 \) deci \( [x_n] \)=n-2 .
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